Without running it, predict exactly what this Python program prints when run with CPython 3.13. Every character counts, including spaces inside lines.

```python
from collections import defaultdict
import itertools

def make_ops():
    ops = []
    for k in range(3):
        ops.append(lambda x, k=k if k % 2 else None: (x, k))
    return ops

print([op(1) for op in make_ops()])

def gen(n):
    total = 0
    for i in range(n):
        got = yield i * i
        total += got or i
    return total

g = gen(4)
out = [next(g)]
out.append(g.send(10))
out.append(next(g))
try:
    while True:
        out.append(g.send(-1))
except StopIteration as e:
    out.append(("done", e.value))
print(out)

d = defaultdict(list)
for word in "tide pool tide surf pool tide".split():
    d[len(word)].append(word)
d[3]
print({k: sorted(set(v)) for k, v in sorted(d.items(), key=lambda kv: (-len(kv[1]), kv[0]))})

a = [1, 2, 3]
b = a
a += [4]
a = a + [5]
print(a, b, a is b)

s = "Agentic Weekly"
print(s[::-3], s[-1:-8:-2], s[3:1], len(s.split("e")))

nums = [3, 1, 2]
it = iter(nums)
pairs = list(zip(it, it))
print(pairs, list(it), sorted(nums, key=lambda v: -v)[1:])

print(list(itertools.accumulate([1, 2, 3, 4], lambda acc, v: acc * v if v % 2 == 0 else acc + v)))
print(f"{7/2:.0f} {round(2.5)} {round(3.5)} {-7 // 2} {-7 % 3} {2 ** -1}")
try:
    print({True: "a", 1: "b", 1.0: "c"})
finally:
    print(0.1 + 0.2 == 0.3, abs(0.1 + 0.2 - 0.3) < 1e-9)
```

Reply with the complete standard output in ONE fenced ```text code block (one output line per line, nothing else inside the block). You may reason before the block.